Japheth had three bags of sesame seeds, N, P and Q and the mass of each bag of sesame seeds was in the ratio 2 : 3 : 1. Japheth decided to transfer 30% of sesame seeds from Bag N into Bag P and 70% of sesame seeds from Bag Q into Bag P. Given that the mass of Bag P was 43 kg in the end, how many kilograms of sesame seeds were transferred into Bag P?
|
N |
P |
Q |
Before |
2 u |
3 u |
1 u |
Change 1 |
- 0.6 u |
+ 0.6 u |
|
Change 2 |
|
+ 0.7 u |
- 0.7 u |
After |
1.4 u |
4.3 u |
0.3 u |
Mass of sesame seeds transferred from Bag N into Bag P
= 30% x 2 u
=
30100 x 2 u
= 1.4 u
Mass of sesame seeds transferred from Bag Q into Bag P
= 70% x 1 u
=
70100 x 1 u
= 0.7 u
Mass of sesame seeds in Bag P in the end
= 3 u + 0.6 u + 0.7 u
= 4.3 u
4.3 u = 43
1 u = 43 ÷ 4.3 = 10
Mass of sesame seeds transferred into Bag P
= 0.6 u + 0.7 u
= 1.3 u
= 1.3 x 10
= 13 kg
Answer(s): 13 kg