Albert had three bags of sesame seeds, J, K and L and the mass of each bag of sesame seeds was in the ratio 1 : 1 : 1. Albert decided to transfer 20% of sesame seeds from Bag J into Bag K and 70% of sesame seeds from Bag L into Bag K. Given that the mass of Bag K was 5.7 kg in the end, how many kilograms of sesame seeds were transferred into Bag K?

	J	K	L
Before	1 u	1 u	1 u
Change 1	- 0.2 u	+ 0.2 u
Change 2		+ 0.7 u	- 0.7 u
After	0.8 u	1.9 u	0.3 u

Mass of sesame seeds transferred from Bag J into Bag K
= 20% x 1 u
= ²⁰₁₀₀ x 1 u
= 0.8 u

Mass of sesame seeds transferred from Bag L into Bag K
= 70% x 1 u
= ⁷⁰₁₀₀ x 1 u
= 0.7 u

Mass of sesame seeds in Bag K in the end
= 1 u + 0.2 u + 0.7 u
= 1.9 u

1.9 u = 5.7 

1 u = 5.7 ÷ 1.9 = 3

Mass of sesame seeds transferred into Bag K
= 0.2 u + 0.7 u
= 0.9 u
= 0.9 x 3
= 2.7 kg

Answer(s): 2.7 kg