Cody had three bags of flour, M, N and P and the mass of each bag of flour was in the ratio 1 : 1 : 1. Cody decided to transfer 10% of flour from Bag M into Bag N and 90% of flour from Bag P into Bag N. Given that the mass of Bag N was 4 kg in the end, how many kilograms of flour were transferred into Bag N?
| |
M |
N |
P |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
- 0.1 u |
+ 0.1 u |
|
| Change 2 |
|
+ 0.9 u |
- 0.9 u |
| After |
0.9 u |
2 u |
0.1 u |
Mass of flour transferred from Bag M into Bag N
= 10% x 1 u
=
10100 x 1 u
= 0.9 u
Mass of flour transferred from Bag P into Bag N
= 90% x 1 u
=
90100 x 1 u
= 0.9 u
Mass of flour in Bag N in the end
= 1 u + 0.1 u + 0.9 u
= 2 u
2 u = 4
1 u = 4 ÷ 2 = 2
Mass of flour transferred into Bag N
= 0.1 u + 0.9 u
= 1 u
= 1 x 2
= 2 kg
Answer(s): 2 kg
