Eric had three bags of flour, U, V and W and the mass of each bag of flour was in the ratio 3 : 4 : 3. Eric decided to transfer 10% of flour from Bag U into Bag V and 70% of flour from Bag W into Bag V. Given that the mass of Bag V was 32 kg in the end, how many kilograms of flour were transferred into Bag V?
| |
U |
V |
W |
| Before |
3 u |
4 u |
3 u |
| Change 1 |
- 0.3 u |
+ 0.3 u |
|
| Change 2 |
|
+ 2.1 u |
- 2.1 u |
| After |
2.7 u |
6.4 u |
0.9 u |
Mass of flour transferred from Bag U into Bag V
= 10% x 3 u
=
10100 x 3 u
= 2.7 u
Mass of flour transferred from Bag W into Bag V
= 70% x 3 u
=
70100 x 3 u
= 2.1 u
Mass of flour in Bag V in the end
= 4 u + 0.3 u + 2.1 u
= 6.4 u
6.4 u = 32
1 u = 32 ÷ 6.4 = 5
Mass of flour transferred into Bag V
= 0.3 u + 2.1 u
= 2.4 u
= 2.4 x 5
= 12 kg
Answer(s): 12 kg
