Liam had three bags of flour, A, B and C and the mass of each bag of flour was in the ratio 1 : 5 : 3. Liam decided to transfer 30% of flour from Bag A into Bag B and 60% of flour from Bag C into Bag B. Given that the mass of Bag B was 21.3 kg in the end, how many kilograms of flour were transferred into Bag B?
| |
A |
B |
C |
| Before |
1 u |
5 u |
3 u |
| Change 1 |
- 0.3 u |
+ 0.3 u |
|
| Change 2 |
|
+ 1.8 u |
- 1.8 u |
| After |
0.7 u |
7.1 u |
1.2 u |
Mass of flour transferred from Bag A into Bag B
= 30% x 1 u
=
30100 x 1 u
= 0.7 u
Mass of flour transferred from Bag C into Bag B
= 60% x 3 u
=
60100 x 3 u
= 1.8 u
Mass of flour in Bag B in the end
= 5 u + 0.3 u + 1.8 u
= 7.1 u
7.1 u = 21.3
1 u = 21.3 ÷ 7.1 = 3
Mass of flour transferred into Bag B
= 0.3 u + 1.8 u
= 2.1 u
= 2.1 x 3
= 6.3 kg
Answer(s): 6.3 kg
