Eric had three bags of green beans, C, D and E and the mass of each bag of green beans was in the ratio 2 : 2 : 5. Eric decided to transfer 30% of green beans from Bag C into Bag D and 60% of green beans from Bag E into Bag D. Given that the mass of Bag D was 11.2 kg in the end, how many kilograms of green beans were transferred into Bag D?

	C	D	E
Before	2 u	2 u	5 u
Change 1	- 0.6 u	+ 0.6 u
Change 2		+ 3 u	- 3 u
After	1.4 u	5.6 u	2 u

Mass of green beans transferred from Bag C into Bag D
= 30% x 2 u
= ³⁰₁₀₀ x 2 u
= 1.4 u

Mass of green beans transferred from Bag E into Bag D
= 60% x 5 u
= ⁶⁰₁₀₀ x 5 u
= 3 u

Mass of green beans in Bag D in the end
= 2 u + 0.6 u + 3 u
= 5.6 u

5.6 u = 11.2 

1 u = 11.2 ÷ 5.6 = 2

Mass of green beans transferred into Bag D
= 0.6 u + 3 u
= 3.6 u
= 3.6 x 2
= 7.2 kg

Answer(s): 7.2 kg