Glen had three bags of oats, F, G and H and the mass of each bag of oats was in the ratio 1 : 1 : 1. Glen decided to transfer 30% of oats from Bag F into Bag G and 90% of oats from Bag H into Bag G. Given that the mass of Bag G was 6.6 kg in the end, how many kilograms of oats were transferred into Bag G?
| |
F |
G |
H |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
- 0.3 u |
+ 0.3 u |
|
| Change 2 |
|
+ 0.9 u |
- 0.9 u |
| After |
0.7 u |
2.2 u |
0.1 u |
Mass of oats transferred from Bag F into Bag G
= 30% x 1 u
=
30100 x 1 u
= 0.7 u
Mass of oats transferred from Bag H into Bag G
= 90% x 1 u
=
90100 x 1 u
= 0.9 u
Mass of oats in Bag G in the end
= 1 u + 0.3 u + 0.9 u
= 2.2 u
2.2 u = 6.6
1 u = 6.6 ÷ 2.2 = 3
Mass of oats transferred into Bag G
= 0.3 u + 0.9 u
= 1.2 u
= 1.2 x 3
= 3.6 kg
Answer(s): 3.6 kg
