Riordan had three bags of peppercorns, G, H and J and the mass of each bag of peppercorns was in the ratio 4 : 4 : 5. Riordan decided to transfer 10% of peppercorns from Bag G into Bag H and 90% of peppercorns from Bag J into Bag H. Given that the mass of Bag H was 35.6 kg in the end, how many kilograms of peppercorns were transferred into Bag H?

	G	H	J
Before	4 u	4 u	5 u
Change 1	- 0.4 u	+ 0.4 u
Change 2		+ 4.5 u	- 4.5 u
After	3.6 u	8.9 u	0.5 u

Mass of peppercorns transferred from Bag G into Bag H
= 10% x 4 u
= ¹⁰₁₀₀ x 4 u
= 3.6 u

Mass of peppercorns transferred from Bag J into Bag H
= 90% x 5 u
= ⁹⁰₁₀₀ x 5 u
= 4.5 u

Mass of peppercorns in Bag H in the end
= 4 u + 0.4 u + 4.5 u
= 8.9 u

8.9 u = 35.6 

1 u = 35.6 ÷ 8.9 = 4

Mass of peppercorns transferred into Bag H
= 0.4 u + 4.5 u
= 4.9 u
= 4.9 x 4
= 19.6 kg

Answer(s): 19.6 kg