George had three bags of corn starch, L, M and N and the mass of each bag of corn starch was in the ratio 3 : 4 : 1. George decided to transfer 30% of corn starch from Bag L into Bag M and 60% of corn starch from Bag N into Bag M. Given that the mass of Bag M was 33 kg in the end, how many kilograms of corn starch were transferred into Bag M?

	L	M	N
Before	3 u	4 u	1 u
Change 1	- 0.9 u	+ 0.9 u
Change 2		+ 0.6 u	- 0.6 u
After	2.1 u	5.5 u	0.4 u

Mass of corn starch transferred from Bag L into Bag M
= 30% x 3 u
= ³⁰₁₀₀ x 3 u
= 2.1 u

Mass of corn starch transferred from Bag N into Bag M
= 60% x 1 u
= ⁶⁰₁₀₀ x 1 u
= 0.6 u

Mass of corn starch in Bag M in the end
= 4 u + 0.9 u + 0.6 u
= 5.5 u

5.5 u = 33 

1 u = 33 ÷ 5.5 = 6

Mass of corn starch transferred into Bag M
= 0.9 u + 0.6 u
= 1.5 u
= 1.5 x 6
= 9 kg

Answer(s): 9 kg