Fabian had three bags of black beans, F, G and H and the mass of each bag of black beans was in the ratio 3 : 1 : 2. Fabian decided to transfer 30% of black beans from Bag F into Bag G and 70% of black beans from Bag H into Bag G. Given that the mass of Bag G was 6.6 kg in the end, how many kilograms of black beans were transferred into Bag G?

	F	G	H
Before	3 u	1 u	2 u
Change 1	- 0.9 u	+ 0.9 u
Change 2		+ 1.4 u	- 1.4 u
After	2.1 u	3.3 u	0.6 u

Mass of black beans transferred from Bag F into Bag G
= 30% x 3 u
= ³⁰₁₀₀ x 3 u
= 2.1 u

Mass of black beans transferred from Bag H into Bag G
= 70% x 2 u
= ⁷⁰₁₀₀ x 2 u
= 1.4 u

Mass of black beans in Bag G in the end
= 1 u + 0.9 u + 1.4 u
= 3.3 u

3.3 u = 6.6 

1 u = 6.6 ÷ 3.3 = 2

Mass of black beans transferred into Bag G
= 0.9 u + 1.4 u
= 2.3 u
= 2.3 x 2
= 4.6 kg

Answer(s): 4.6 kg