The area of the rectangle to the area of the triangle in the figure is in the ratio 3 : 4. After the shaded rectangle of width 7 cm is removed from the figure, the ratio of the remaining area of the rectangle to the remaining area of the triangle is 4 : 7. Given that the area of the triangle is 42 cm
2 more than the area of the rectangle, find the length of the shaded rectangle that is being removed.
|
Rectangle |
Triangle |
Difference |
Total |
3x3 = 9 u |
4x3 = 12 u |
1x3 = 3 u |
Removed |
- 5 u |
- 5 u |
|
Left |
4 u |
7 u |
3 u |
The difference in the areas between the rectangle and the triangle remains unchanged. Make the difference the same. LCM of 1 and 3 is 3.
Difference in areas between the triangle and the rectangle
= 12 u - 9 u
= 3 u
3 u = 42
1 u = 42 ÷ 3 = 14
Area of the rectangle that is removed
= 5 u
= 5 x 14
= 70 cm
2 Length of the shaded rectangle that is removed
= 70 ÷ 7
= 10 cm
Answer(s): 10 cm