The area of the rectangle to the area of the triangle in the figure is in the ratio 2 : 3. After the shaded rectangle of length 8 cm is removed from the figure, the ratio of the remaining area of the rectangle to the remaining area of the triangle is 3 : 5. Given that the area of the triangle is 48 cm
2 more than the area of the rectangle, find the width of the shaded rectangle that is being removed.
|
Rectangle |
Triangle |
Difference |
Total |
2x2 = 4 u |
3x2 = 6 u |
1x2 = 2 u |
Removed |
- 1 u |
- 1 u |
|
Left |
3 u |
5 u |
2 u |
The difference in the areas between the rectangle and the triangle remains unchanged. Make the difference the same. LCM of 1 and 2 is 2.
Difference in areas between the triangle and the rectangle
= 6 u - 4 u
= 2 u
2 u = 48
1 u = 48 ÷ 2 = 24
Area of the rectangle that is removed
= 1 u
= 1 x 24
= 24 cm
2 Width of the shaded rectangle that is removed
= 24 ÷ 8
= 3 cm
Answer(s): 3 cm