Vincent saved some 50-cent coins and $10 notes in his coin box. The total value of the 50-cent coins to the total value of the $10 notes he had was in the ratio 1 : 3. After $30 worth of 50-cent coins and an equal value of $10 notes were added to the coin box, the ratio of the total value of 50-cent coins to the total value of $10 notes became 5 : 12. How many of each type did Vincent have in the end?
- 50-cent coins?
- $10 notes?
|
Value of 50-cent |
Value of $10 |
Difference in value |
Before |
1x7 = 7 u |
3x7 = 21 u |
2x7 = 14 u |
Change |
+ 30 |
+ 30 |
|
After |
5x2 = 10 u |
12x2 = 24 u |
7x2 = 14 u |
(a)
The difference in values between 50-cent and $10 remains unchanged. Make the difference in value the same. LCM of 2 and 7 is 14.
Increase in the value of 50-cent coins after more were added
= 10 u - 7 u
= 3 u
3 u = 30
1 u = 30 ÷ 3 = 10
Value of 50-cent coins in the end
= 10 u
= 10 x 10
= $100
100¢ = $1
50¢ = $0.50
Number of 50-cent coins in the end
= 100 ÷ 0.50
= 200
(b)
Value of $10 notes in the end
= 24 u
= 24 x 10
= $240
Number of $10 notes in the end
= 240 ÷ 10
= 24
Answer(s): (a) 200; (b) 24