Tom saved some 10-cent coins and $1 notes in his coin box. The total value of the 10-cent coins to the total value of the $1 notes he had was in the ratio 4 : 7. After $12 worth of 10-cent coins and an equal value of $1 notes were added to the coin box, the ratio of the total value of 10-cent coins to the total value of $1 notes became 2 : 3. How many of each type did Tom have in the end?
- 10-cent coins?
- $1 notes?
|
Value of 10-cent |
Value of $1 |
Difference in value |
Before |
4x1 = 4 u |
7x1 = 7 u |
3x1 = 3 u |
Change |
+ 12 |
+ 12 |
|
After |
2x3 = 6 u |
3x3 = 9 u |
1x3 = 3 u |
(a)
The difference in values between 10-cent and $1 remains unchanged. Make the difference in value the same. LCM of 3 and 1 is 3.
Increase in the value of 10-cent coins after more were added
= 6 u - 4 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Value of 10-cent coins in the end
= 6 u
= 6 x 6
= $36
100¢ = $1
10¢ = $0.10
Number of 10-cent coins in the end
= 36 ÷ 0.10
= 360
(b)
Value of $1 notes in the end
= 9 u
= 9 x 6
= $54
Number of $1 notes in the end
= 54 ÷ 1
= 54
Answer(s): (a) 360; (b) 54