Bobby saved some 50-cent coins and $2 notes in his coin box. The total value of the 50-cent coins to the total value of the $2 notes he had was in the ratio 2 : 7. After $64 worth of 50-cent coins and an equal value of $2 notes were added to the coin box, the ratio of the total value of 50-cent coins to the total value of $2 notes became 2 : 3. How many of each type did Bobby have in the end?
- 50-cent coins?
- $2 notes?
|
Value of 50-cent |
Value of $2 |
Difference in value |
Before |
2x1 = 2 u |
7x1 = 7 u |
5x1 = 5 u |
Change |
+ 64 |
+ 64 |
|
After |
2x5 = 10 u |
3x5 = 15 u |
1x5 = 5 u |
(a)
The difference in values between 50-cent and $2 remains unchanged. Make the difference in value the same. LCM of 5 and 1 is 5.
Increase in the value of 50-cent coins after more were added
= 10 u - 2 u
= 8 u
8 u = 64
1 u = 64 ÷ 8 = 8
Value of 50-cent coins in the end
= 10 u
= 10 x 8
= $80
100¢ = $1
50¢ = $0.50
Number of 50-cent coins in the end
= 80 ÷ 0.50
= 160
(b)
Value of $2 notes in the end
= 15 u
= 15 x 8
= $120
Number of $2 notes in the end
= 120 ÷ 2
= 60
Answer(s): (a) 160; (b) 60