Bryan saved some 50-cent coins and $1 notes in his coin box. The total value of the 50-cent coins to the total value of the $1 notes he had was in the ratio 1 : 5. After $140 worth of 50-cent coins and an equal value of $1 notes were added to the coin box, the ratio of the total value of 50-cent coins to the total value of $1 notes became 9 : 10. How many of each type did Bryan have in the end?
- 50-cent coins?
- $1 notes?
|
Value of 50-cent |
Value of $1 |
Difference in value |
Before |
1x1 = 1 u |
5x1 = 5 u |
4x1 = 4 u |
Change |
+ 140 |
+ 140 |
|
After |
9x4 = 36 u |
10x4 = 40 u |
1x4 = 4 u |
(a)
The difference in values between 50-cent and $1 remains unchanged. Make the difference in value the same. LCM of 4 and 1 is 4.
Increase in the value of 50-cent coins after more were added
= 36 u - 1 u
= 35 u
35 u = 140
1 u = 140 ÷ 35 = 4
Value of 50-cent coins in the end
= 36 u
= 36 x 4
= $144
100¢ = $1
50¢ = $0.50
Number of 50-cent coins in the end
= 144 ÷ 0.50
= 288
(b)
Value of $1 notes in the end
= 40 u
= 40 x 4
= $160
Number of $1 notes in the end
= 160 ÷ 1
= 160
Answer(s): (a) 288; (b) 160