Sean saved some 50-cent coins and $5 notes in his coin box. The total value of the 50-cent coins to the total value of the $5 notes he had was in the ratio 4 : 9. After $104 worth of 50-cent coins and an equal value of $5 notes were added to the coin box, the ratio of the total value of 50-cent coins to the total value of $5 notes became 6 : 7. How many of each type did Sean have in the end?
- 50-cent coins?
- $5 notes?
|
Value of 50-cent |
Value of $5 |
Difference in value |
Before |
4x1 = 4 u |
9x1 = 9 u |
5x1 = 5 u |
Change |
+ 104 |
+ 104 |
|
After |
6x5 = 30 u |
7x5 = 35 u |
1x5 = 5 u |
(a)
The difference in values between 50-cent and $5 remains unchanged. Make the difference in value the same. LCM of 5 and 1 is 5.
Increase in the value of 50-cent coins after more were added
= 30 u - 4 u
= 26 u
26 u = 104
1 u = 104 ÷ 26 = 4
Value of 50-cent coins in the end
= 30 u
= 30 x 4
= $120
100¢ = $1
50¢ = $0.50
Number of 50-cent coins in the end
= 120 ÷ 0.50
= 240
(b)
Value of $5 notes in the end
= 35 u
= 35 x 4
= $140
Number of $5 notes in the end
= 140 ÷ 5
= 28
Answer(s): (a) 240; (b) 28