Hazel made buns for sale. 55% of the buns were beef buns and the rest were kaya and chicken buns in the ratio 2 : 1. If a customer bought 65% of the beef buns and all of the chicken buns, what percentage of the kaya buns must Hazel sell for her to maintain the original percentage of beef buns at first? Leave your answer in decimals and correct to 1 decimal place.
Beef buns |
Kaya buns |
Chicken buns |
11 u |
9 u |
|
6 u |
3 u |
|
Beef buns |
Kaya buns |
Chicken buns |
Total buns |
Before |
11 u |
6 u |
3 u |
20 u |
Change |
- 7.15 u |
- 2.85 u |
- 3 u |
|
After |
3.85 u |
3.15 u |
0 |
7 u |
55% =
55100 =
112065% =
65100 =
1320 Total number of buns = 20 u
Number of kaya and chicken buns
= 20 u - 11 u
= 9 u
Number of kaya buns at first
=
23 x 9 u
= 6 u
Number of chicken buns at first
= 9 u - 6 u
= 3 u
Number of beef buns sold
= 65% x 11 u
=
65100 x 11 u
=
1320 x 11 u
= 7.15 u
Number of chicken buns sold
=
13 x 9 u
= 3 u
Number of beef buns left
= 11 u - 7.15 u
= 3.85 u
To maintain the percentage of the beef buns in the end,
55% → 3.85 u
100% →
3.8555 x 100 = 7 u
Total number of buns in the end to maintain the original percentage of beef buns = 7 u
Number of kaya buns left
= 7 u - 3.85 u
= 3.15 u
Number of kaya buns that Hazel must sell to maintain the original percentage of beef buns
= 6 u - 3.15 u
= 2.85 u
Percentage of the kaya buns that Hazel must sell
=
2.856 x 100%
= 47.5%
Answer(s): 47.5%