Jayden bought 88 pencils and Riordan bought 97 pencils. After Riordan used
35 times as many pencils as Jayden, he was left with four times as many pencils as Jayden. How many pencils did each of them have in the end?
- Jayden
- Riordan
| |
Make p the same.
(1)x4 = (3) |
Jayden
(1) |
Riordan
(2) |
| Before |
352 |
88 |
97 |
| Change |
- 20 u |
- 5 u |
- 3 u |
| After |
4 p |
1 p |
4 p |
(a)
88 - 5 u = 1 p --- (1)
97 - 3 u =
4 p --- (2)
(1)
x4
352 - 20 u =
4 p --- (3)
(3) = (2)
97 - 3 u = 352 - 20 u
20 u - 3 u = 352 - 97
17 u = 255
1 u = 255 ÷ 17 = 15
Number of pencils that Jayden had in the end
= 88 - 5 u
= 88 - 5 x 15
= 88 - 75
= 13
(b)
1 p = 13
Number of pencils that Riordan had in the end
= 4 p
= 4 x 13
= 52
Answer(s): (a) 13; (b) 52
