Jamie bought 41 markers and Paul bought 74 markers. After Paul used
25 times as many markers as Jamie, he was left with four times as many markers as Jamie. How many markers did each of them have in the end?
- Jamie
- Paul
| |
Make p the same.
(1)x4 = (3) |
Jamie
(1) |
Paul
(2) |
| Before |
164 |
41 |
74 |
| Change |
- 20 u |
- 5 u |
- 2 u |
| After |
4 p |
1 p |
4 p |
(a)
41 - 5 u = 1 p --- (1)
74 - 2 u =
4 p --- (2)
(1)
x4
164 - 20 u =
4 p --- (3)
(3) = (2)
74 - 2 u = 164 - 20 u
20 u - 2 u = 164 - 74
18 u = 90
1 u = 90 ÷ 18 = 5
Number of markers that Jamie had in the end
= 41 - 5 u
= 41 - 5 x 5
= 41 - 25
= 16
(b)
1 p = 16
Number of markers that Paul had in the end
= 4 p
= 4 x 16
= 64
Answer(s): (a) 16; (b) 64
