Lucas bought 49 pens and Brandon bought 92 pens. After Brandon used
27 times as many pens as Lucas, he was left with four times as many pens as Lucas. How many pens did each of them have in the end?
- Lucas
- Brandon
| |
Make p the same.
(1)x4 = (3) |
Lucas
(1) |
Brandon
(2) |
| Before |
196 |
49 |
92 |
| Change |
- 28 u |
- 7 u |
- 2 u |
| After |
4 p |
1 p |
4 p |
(a)
49 - 7 u = 1 p --- (1)
92 - 2 u =
4 p --- (2)
(1)
x4
196 - 28 u =
4 p --- (3)
(3) = (2)
92 - 2 u = 196 - 28 u
28 u - 2 u = 196 - 92
26 u = 104
1 u = 104 ÷ 26 = 4
Number of pens that Lucas had in the end
= 49 - 7 u
= 49 - 7 x 4
= 49 - 28
= 21
(b)
1 p = 21
Number of pens that Brandon had in the end
= 4 p
= 4 x 21
= 84
Answer(s): (a) 21; (b) 84
