Christian bought 51 markers and Liam bought 95 markers. After Liam used
37 times as many markers as Christian, he was left with five times as many markers as Christian. How many markers did each of them have in the end?
- Christian
- Liam
| |
Make p the same.
(1)x5 = (3) |
Christian
(1) |
Liam
(2) |
| Before |
255 |
51 |
95 |
| Change |
- 35 u |
- 7 u |
- 3 u |
| After |
5 p |
1 p |
5 p |
(a)
51 - 7 u = 1 p --- (1)
95 - 3 u =
5 p --- (2)
(1)
x5
255 - 35 u =
5 p --- (3)
(3) = (2)
95 - 3 u = 255 - 35 u
35 u - 3 u = 255 - 95
32 u = 160
1 u = 160 ÷ 32 = 5
Number of markers that Christian had in the end
= 51 - 7 u
= 51 - 7 x 5
= 51 - 35
= 16
(b)
1 p = 16
Number of markers that Liam had in the end
= 5 p
= 5 x 16
= 80
Answer(s): (a) 16; (b) 80
