Gavin bought 61 pencils and Neave bought 93 pencils. After Neave used
37 times as many pencils as Gavin, he was left with thrice as many pencils as Gavin. How many pencils did each of them have in the end?
- Gavin
- Neave
| |
Make p the same.
(1)x3 = (3) |
Gavin
(1) |
Neave
(2) |
| Before |
183 |
61 |
93 |
| Change |
- 21 u |
- 7 u |
- 3 u |
| After |
3 p |
1 p |
3 p |
(a)
61 - 7 u = 1 p --- (1)
93 - 3 u =
3 p --- (2)
(1)
x3
183 - 21 u =
3 p --- (3)
(3) = (2)
93 - 3 u = 183 - 21 u
21 u - 3 u = 183 - 93
18 u = 90
1 u = 90 ÷ 18 = 5
Number of pencils that Gavin had in the end
= 61 - 7 u
= 61 - 7 x 5
= 61 - 35
= 26
(b)
1 p = 26
Number of pencils that Neave had in the end
= 3 p
= 3 x 26
= 78
Answer(s): (a) 26; (b) 78
