Noah bought 57 markers and Wesley bought 81 markers. After Wesley used
37 times as many markers as Noah, he was left with thrice as many markers as Noah. How many markers did each of them have in the end?
- Noah
- Wesley
| |
Make p the same.
(1)x3 = (3) |
Noah
(1) |
Wesley
(2) |
| Before |
171 |
57 |
81 |
| Change |
- 21 u |
- 7 u |
- 3 u |
| After |
3 p |
1 p |
3 p |
(a)
57 - 7 u = 1 p --- (1)
81 - 3 u =
3 p --- (2)
(1)
x3
171 - 21 u =
3 p --- (3)
(3) = (2)
81 - 3 u = 171 - 21 u
21 u - 3 u = 171 - 81
18 u = 90
1 u = 90 ÷ 18 = 5
Number of markers that Noah had in the end
= 57 - 7 u
= 57 - 7 x 5
= 57 - 35
= 22
(b)
1 p = 22
Number of markers that Wesley had in the end
= 3 p
= 3 x 22
= 66
Answer(s): (a) 22; (b) 66
