Harris bought 85 markers and Tom bought 93 markers. After Tom used
37 times as many markers as Harris, he was left with thrice as many markers as Harris. How many markers did each of them have in the end?
- Harris
- Tom
| |
Make p the same.
(1)x3 = (3) |
Harris
(1) |
Tom
(2) |
| Before |
255 |
85 |
93 |
| Change |
- 21 u |
- 7 u |
- 3 u |
| After |
3 p |
1 p |
3 p |
(a)
85 - 7 u = 1 p --- (1)
93 - 3 u =
3 p --- (2)
(1)
x3
255 - 21 u =
3 p --- (3)
(3) = (2)
93 - 3 u = 255 - 21 u
21 u - 3 u = 255 - 93
18 u = 162
1 u = 162 ÷ 18 = 9
Number of markers that Harris had in the end
= 85 - 7 u
= 85 - 7 x 9
= 85 - 63
= 22
(b)
1 p = 22
Number of markers that Tom had in the end
= 3 p
= 3 x 22
= 66
Answer(s): (a) 22; (b) 66
