Leah bought 46 pens and Wesley bought 62 pens. After Wesley used
27 times as many pens as Leah, he was left with thrice as many pens as Leah. How many pens did each of them have in the end?
- Leah
- Wesley
| |
Make p the same.
(1)x3 = (3) |
Leah
(1) |
Wesley
(2) |
| Before |
138 |
46 |
62 |
| Change |
- 21 u |
- 7 u |
- 2 u |
| After |
3 p |
1 p |
3 p |
(a)
46 - 7 u = 1 p --- (1)
62 - 2 u =
3 p --- (2)
(1)
x3
138 - 21 u =
3 p --- (3)
(3) = (2)
62 - 2 u = 138 - 21 u
21 u - 2 u = 138 - 62
19 u = 76
1 u = 76 ÷ 19 = 4
Number of pens that Leah had in the end
= 46 - 7 u
= 46 - 7 x 4
= 46 - 28
= 18
(b)
1 p = 18
Number of pens that Wesley had in the end
= 3 p
= 3 x 18
= 54
Answer(s): (a) 18; (b) 54
