Julian bought 63 markers and Glen bought 78 markers. After Glen used
25 times as many markers as Julian, he was left with twice as many markers as Julian. How many markers did each of them have in the end?
- Julian
- Glen
| |
Make p the same.
(1)x2 = (3) |
Julian
(1) |
Glen
(2) |
| Before |
126 |
63 |
78 |
| Change |
- 10 u |
- 5 u |
- 2 u |
| After |
2 p |
1 p |
2 p |
(a)
63 - 5 u = 1 p --- (1)
78 - 2 u =
2 p --- (2)
(1)
x2
126 - 10 u =
2 p --- (3)
(3) = (2)
78 - 2 u = 126 - 10 u
10 u - 2 u = 126 - 78
8 u = 48
1 u = 48 ÷ 8 = 6
Number of markers that Julian had in the end
= 63 - 5 u
= 63 - 5 x 6
= 63 - 30
= 33
(b)
1 p = 33
Number of markers that Glen had in the end
= 2 p
= 2 x 33
= 66
Answer(s): (a) 33; (b) 66
