Harris bought 40 pens and Rael bought 68 pens. After Rael used
27 times as many pens as Harris, he was left with five times as many pens as Harris. How many pens did each of them have in the end?
- Harris
- Rael
| |
Make p the same.
(1)x5 = (3) |
Harris
(1) |
Rael
(2) |
| Before |
200 |
40 |
68 |
| Change |
- 35 u |
- 7 u |
- 2 u |
| After |
5 p |
1 p |
5 p |
(a)
40 - 7 u = 1 p --- (1)
68 - 2 u =
5 p --- (2)
(1)
x5
200 - 35 u =
5 p --- (3)
(3) = (2)
68 - 2 u = 200 - 35 u
35 u - 2 u = 200 - 68
33 u = 132
1 u = 132 ÷ 33 = 4
Number of pens that Harris had in the end
= 40 - 7 u
= 40 - 7 x 4
= 40 - 28
= 12
(b)
1 p = 12
Number of pens that Rael had in the end
= 5 p
= 5 x 12
= 60
Answer(s): (a) 12; (b) 60
