Victoria bought 51 markers and Sam bought 54 markers. After Sam used
27 times as many markers as Victoria, he was left with twice as many markers as Victoria. How many markers did each of them have in the end?
- Victoria
- Sam
|
Make p the same. (1)x2 = (3) |
Victoria (1) |
Sam (2) |
Before |
102 |
51 |
54 |
Change |
- 14 u |
- 7 u |
- 2 u |
After |
2 p |
1 p |
2 p |
(a)
51 - 7 u = 1 p --- (1)
54 - 2 u =
2 p --- (2)
(1)
x2
102 - 14 u =
2 p --- (3)
(3) = (2)
54 - 2 u = 102 - 14 u
14 u - 2 u = 102 - 54
12 u = 48
1 u = 48 ÷ 12 = 4
Number of markers that Victoria had in the end
= 51 - 7 u
= 51 - 7 x 4
= 51 - 28
= 23
(b)
1 p = 23
Number of markers that Sam had in the end
= 2 p
= 2 x 23
= 46
Answer(s): (a) 23; (b) 46