Isaac bought 92 markers and Perry bought 98 markers. After Perry used
25 times as many markers as Isaac, he was left with four times as many markers as Isaac. How many markers did each of them have in the end?
- Isaac
- Perry
| |
Make p the same.
(1)x4 = (3) |
Isaac
(1) |
Perry
(2) |
| Before |
368 |
92 |
98 |
| Change |
- 20 u |
- 5 u |
- 2 u |
| After |
4 p |
1 p |
4 p |
(a)
92 - 5 u = 1 p --- (1)
98 - 2 u =
4 p --- (2)
(1)
x4
368 - 20 u =
4 p --- (3)
(3) = (2)
98 - 2 u = 368 - 20 u
20 u - 2 u = 368 - 98
18 u = 270
1 u = 270 ÷ 18 = 15
Number of markers that Isaac had in the end
= 92 - 5 u
= 92 - 5 x 15
= 92 - 75
= 17
(b)
1 p = 17
Number of markers that Perry had in the end
= 4 p
= 4 x 17
= 68
Answer(s): (a) 17; (b) 68
