Simon bought 140 brown and green balloons for a party. The number of green balloons was
37 times as many as the number of brown balloons. Simon used
14 times as many green balloons as brown balloons and was left with twice as many green balloons as brown balloons. How many balloons did Simon have in the end?
|
Green (1) |
Brown (2) |
Make b the same. (2)x2 = (3) |
Before |
42 |
98 |
196 |
Change |
- 1 p |
- 4 p |
- 8 p |
After |
2 b |
1 b |
2 b |
Number of green balloons that Simon bought at first = 3 u
Number of brown balloons that Simon bought at first = 7 u
Total number of balloons at first
= 3 u + 7 u
= 10 u
10 u = 140
1 u = 140 ÷ 10 = 14
Number of green balloons at first
= 3 u
= 3 x 14
= 42
Number of brown balloons at first
= 7 u
= 7 x 14
= 98
42 - 1 p =
2 b --- (1)
98 - 4 p = 1 b --- (2)
(2)
x2
196 - 8 p =
2 b --- (3)
(3) = (1)
196 - 8 p = 42 - 1 p
8 p - 1 p = 196 - 42
7 p = 154
1 p = 154 ÷ 7 = 22
Number of balloons that Simon used
= 1 p + 4 p
= 5 p
= 5 x 22
= 110
Number of balloons that Simon had in the end
= 140 - 110
= 30
Answer(s): 30