Sean bought 143 grey and brown balloons for a party. The number of brown balloons was
47 times as many as the number of grey balloons. Sean used
13 times as many brown balloons as grey balloons and was left with twice as many brown balloons as grey balloons. How many balloons did Sean have in the end?
|
Brown (1) |
Grey (2) |
Make b the same. (2)x2 = (3) |
Before |
52 |
91 |
182 |
Change |
- 1 p |
- 3 p |
- 6 p |
After |
2 b |
1 b |
2 b |
Number of brown balloons that Sean bought at first = 4 u
Number of grey balloons that Sean bought at first = 7 u
Total number of balloons at first
= 4 u + 7 u
= 11 u
11 u = 143
1 u = 143 ÷ 11 = 13
Number of brown balloons at first
= 4 u
= 4 x 13
= 52
Number of grey balloons at first
= 7 u
= 7 x 13
= 91
52 - 1 p =
2 b --- (1)
91 - 3 p = 1 b --- (2)
(2)
x2
182 - 6 p =
2 b --- (3)
(3) = (1)
182 - 6 p = 52 - 1 p
6 p - 1 p = 182 - 52
5 p = 130
1 p = 130 ÷ 5 = 26
Number of balloons that Sean used
= 1 p + 3 p
= 4 p
= 4 x 26
= 104
Number of balloons that Sean had in the end
= 143 - 104
= 39
Answer(s): 39