Harry bought 110 grey and white balloons for a party. The number of white balloons was
47 times as many as the number of grey balloons. Harry used
12 times as many white balloons as grey balloons and was left with thrice as many white balloons as grey balloons. How many balloons did Harry have in the end?
|
White (1) |
Grey (2) |
Make b the same. (2)x3 = (3) |
Before |
40 |
70 |
210 |
Change |
- 1 p |
- 2 p |
- 6 p |
After |
3 b |
1 b |
3 b |
Number of white balloons that Harry bought at first = 4 u
Number of grey balloons that Harry bought at first = 7 u
Total number of balloons at first
= 4 u + 7 u
= 11 u
11 u = 110
1 u = 110 ÷ 11 = 10
Number of white balloons at first
= 4 u
= 4 x 10
= 40
Number of grey balloons at first
= 7 u
= 7 x 10
= 70
40 - 1 p =
3 b --- (1)
70 - 2 p = 1 b --- (2)
(2)
x3
210 - 6 p =
3 b --- (3)
(3) = (1)
210 - 6 p = 40 - 1 p
6 p - 1 p = 210 - 40
5 p = 170
1 p = 170 ÷ 5 = 34
Number of balloons that Harry used
= 1 p + 2 p
= 3 p
= 3 x 34
= 102
Number of balloons that Harry had in the end
= 110 - 102
= 8
Answer(s): 8