Archie bought 209 purple and silver balloons for a party. The number of silver balloons was
47 times as many as the number of purple balloons. Archie used
13 times as many silver balloons as purple balloons and was left with twice as many silver balloons as purple balloons. How many balloons did Archie have in the end?
|
Silver (1) |
Purple (2) |
Make b the same. (2)x2 = (3) |
Before |
76 |
133 |
266 |
Change |
- 1 p |
- 3 p |
- 6 p |
After |
2 b |
1 b |
2 b |
Number of silver balloons that Archie bought at first = 4 u
Number of purple balloons that Archie bought at first = 7 u
Total number of balloons at first
= 4 u + 7 u
= 11 u
11 u = 209
1 u = 209 ÷ 11 = 19
Number of silver balloons at first
= 4 u
= 4 x 19
= 76
Number of purple balloons at first
= 7 u
= 7 x 19
= 133
76 - 1 p =
2 b --- (1)
133 - 3 p = 1 b --- (2)
(2)
x2
266 - 6 p =
2 b --- (3)
(3) = (1)
266 - 6 p = 76 - 1 p
6 p - 1 p = 266 - 76
5 p = 190
1 p = 190 ÷ 5 = 38
Number of balloons that Archie used
= 1 p + 3 p
= 4 p
= 4 x 38
= 152
Number of balloons that Archie had in the end
= 209 - 152
= 57
Answer(s): 57