Liam bought 120 silver and purple balloons for a party. The number of purple balloons was
35 times as many as the number of silver balloons. Liam used
14 times as many purple balloons as silver balloons and was left with twice as many purple balloons as silver balloons. How many balloons did Liam have in the end?
|
Purple (1) |
Silver (2) |
Make b the same. (2)x2 = (3) |
Before |
45 |
75 |
150 |
Change |
- 1 p |
- 4 p |
- 8 p |
After |
2 b |
1 b |
2 b |
Number of purple balloons that Liam bought at first = 3 u
Number of silver balloons that Liam bought at first = 5 u
Total number of balloons at first
= 3 u + 5 u
= 8 u
8 u = 120
1 u = 120 ÷ 8 = 15
Number of purple balloons at first
= 3 u
= 3 x 15
= 45
Number of silver balloons at first
= 5 u
= 5 x 15
= 75
45 - 1 p =
2 b --- (1)
75 - 4 p = 1 b --- (2)
(2)
x2
150 - 8 p =
2 b --- (3)
(3) = (1)
150 - 8 p = 45 - 1 p
8 p - 1 p = 150 - 45
7 p = 105
1 p = 105 ÷ 7 = 15
Number of balloons that Liam used
= 1 p + 4 p
= 5 p
= 5 x 15
= 75
Number of balloons that Liam had in the end
= 120 - 75
= 45
Answer(s): 45