Gabriel bought 77 brown and silver balloons for a party. The number of silver balloons was ²₅ times as many as the number of brown balloons. Gabriel used ¹₄ times as many silver balloons as brown balloons and was left with thrice as many silver balloons as brown balloons. How many balloons did Gabriel have in the end?

	Silver (1)	Brown (2)	Make b the same. (2)x3 = (3)
Before	22	55	165
Change	- 1 p	- 4 p	- 12 p
After	3 b	1 b	3 b

Number of silver balloons that Gabriel bought at first = 2 u
Number of brown balloons that Gabriel bought at first = 5 u

Total number of balloons at first
= 2 u + 5 u
= 7 u

7 u = 77

1 u = 77 ÷ 7 = 11

Number of silver balloons at first
= 2 u
= 2 x 11
= 22

Number of brown balloons at first
= 5 u
= 5 x 11
= 55

22 - 1 p = 3 b --- (1)
55 - 4 p = 1 b --- (2)

(2)_x3
165 - 12 p = 3 b --- (3)

(3) = (1)
165 - 12 p = 22 - 1 p
12 p - 1 p = 165 - 22 
11 p = 143

1 p = 143 ÷ 11 = 13

Number of balloons that Gabriel used
= 1 p + 4 p
= 5 p
= 5 x 13
= 65

Number of balloons that Gabriel had in the end
= 77 - 65
= 12

Answer(s): 12