Daniel bought 154 brown and green balloons for a party. The number of green balloons was
47 times as many as the number of brown balloons. Daniel used
12 times as many green balloons as brown balloons and was left with four times as many green balloons as brown balloons. How many balloons did Daniel have in the end?
|
Green (1) |
Brown (2) |
Make b the same. (2)x4 = (3) |
Before |
56 |
98 |
392 |
Change |
- 1 p |
- 2 p |
- 8 p |
After |
4 b |
1 b |
4 b |
Number of green balloons that Daniel bought at first = 4 u
Number of brown balloons that Daniel bought at first = 7 u
Total number of balloons at first
= 4 u + 7 u
= 11 u
11 u = 154
1 u = 154 ÷ 11 = 14
Number of green balloons at first
= 4 u
= 4 x 14
= 56
Number of brown balloons at first
= 7 u
= 7 x 14
= 98
56 - 1 p =
4 b --- (1)
98 - 2 p = 1 b --- (2)
(2)
x4
392 - 8 p =
4 b --- (3)
(3) = (1)
392 - 8 p = 56 - 1 p
8 p - 1 p = 392 - 56
7 p = 336
1 p = 336 ÷ 7 = 48
Number of balloons that Daniel used
= 1 p + 2 p
= 3 p
= 3 x 48
= 144
Number of balloons that Daniel had in the end
= 154 - 144
= 10
Answer(s): 10