Tim bought 110 grey and red balloons for a party. The number of red balloons was
47 times as many as the number of grey balloons. Tim used
12 times as many red balloons as grey balloons and was left with thrice as many red balloons as grey balloons. How many balloons did Tim have in the end?
|
Red (1) |
Grey (2) |
Make b the same. (2)x3 = (3) |
Before |
40 |
70 |
210 |
Change |
- 1 p |
- 2 p |
- 6 p |
After |
3 b |
1 b |
3 b |
Number of red balloons that Tim bought at first = 4 u
Number of grey balloons that Tim bought at first = 7 u
Total number of balloons at first
= 4 u + 7 u
= 11 u
11 u = 110
1 u = 110 ÷ 11 = 10
Number of red balloons at first
= 4 u
= 4 x 10
= 40
Number of grey balloons at first
= 7 u
= 7 x 10
= 70
40 - 1 p =
3 b --- (1)
70 - 2 p = 1 b --- (2)
(2)
x3
210 - 6 p =
3 b --- (3)
(3) = (1)
210 - 6 p = 40 - 1 p
6 p - 1 p = 210 - 40
5 p = 170
1 p = 170 ÷ 5 = 34
Number of balloons that Tim used
= 1 p + 2 p
= 3 p
= 3 x 34
= 102
Number of balloons that Tim had in the end
= 110 - 102
= 8
Answer(s): 8