Michael bought 143 grey and black balloons for a party. The number of black balloons was
47 times as many as the number of grey balloons. Michael used
13 times as many black balloons as grey balloons and was left with twice as many black balloons as grey balloons. How many balloons did Michael have in the end?
|
Black (1) |
Grey (2) |
Make b the same. (2)x2 = (3) |
Before |
52 |
91 |
182 |
Change |
- 1 p |
- 3 p |
- 6 p |
After |
2 b |
1 b |
2 b |
Number of black balloons that Michael bought at first = 4 u
Number of grey balloons that Michael bought at first = 7 u
Total number of balloons at first
= 4 u + 7 u
= 11 u
11 u = 143
1 u = 143 ÷ 11 = 13
Number of black balloons at first
= 4 u
= 4 x 13
= 52
Number of grey balloons at first
= 7 u
= 7 x 13
= 91
52 - 1 p =
2 b --- (1)
91 - 3 p = 1 b --- (2)
(2)
x2
182 - 6 p =
2 b --- (3)
(3) = (1)
182 - 6 p = 52 - 1 p
6 p - 1 p = 182 - 52
5 p = 130
1 p = 130 ÷ 5 = 26
Number of balloons that Michael used
= 1 p + 3 p
= 4 p
= 4 x 26
= 104
Number of balloons that Michael had in the end
= 143 - 104
= 39
Answer(s): 39