Ivan bought 112 black and gold balloons for a party. The number of gold balloons was
35 times as many as the number of black balloons. Ivan used
12 times as many gold balloons as black balloons and was left with four times as many gold balloons as black balloons. How many balloons did Ivan have in the end?
|
Gold (1) |
Black (2) |
Make b the same. (2)x4 = (3) |
Before |
42 |
70 |
280 |
Change |
- 1 p |
- 2 p |
- 8 p |
After |
4 b |
1 b |
4 b |
Number of gold balloons that Ivan bought at first = 3 u
Number of black balloons that Ivan bought at first = 5 u
Total number of balloons at first
= 3 u + 5 u
= 8 u
8 u = 112
1 u = 112 ÷ 8 = 14
Number of gold balloons at first
= 3 u
= 3 x 14
= 42
Number of black balloons at first
= 5 u
= 5 x 14
= 70
42 - 1 p =
4 b --- (1)
70 - 2 p = 1 b --- (2)
(2)
x4
280 - 8 p =
4 b --- (3)
(3) = (1)
280 - 8 p = 42 - 1 p
8 p - 1 p = 280 - 42
7 p = 238
1 p = 238 ÷ 7 = 34
Number of balloons that Ivan used
= 1 p + 2 p
= 3 p
= 3 x 34
= 102
Number of balloons that Ivan had in the end
= 112 - 102
= 10
Answer(s): 10