Lee bought 171 brown and yellow balloons for a party. The number of yellow balloons was ⁴₅ times as many as the number of brown balloons. Lee used ¹₄ times as many yellow balloons as brown balloons and was left with thrice as many yellow balloons as brown balloons. How many balloons did Lee have in the end?

	Yellow (1)	Brown (2)	Make b the same. (2)x3 = (3)
Before	76	95	285
Change	- 1 p	- 4 p	- 12 p
After	3 b	1 b	3 b

Number of yellow balloons that Lee bought at first = 4 u
Number of brown balloons that Lee bought at first = 5 u

Total number of balloons at first
= 4 u + 5 u
= 9 u

9 u = 171

1 u = 171 ÷ 9 = 19

Number of yellow balloons at first
= 4 u
= 4 x 19
= 76

Number of brown balloons at first
= 5 u
= 5 x 19
= 95

76 - 1 p = 3 b --- (1)
95 - 4 p = 1 b --- (2)

(2)_x3
285 - 12 p = 3 b --- (3)

(3) = (1)
285 - 12 p = 76 - 1 p
12 p - 1 p = 285 - 76 
11 p = 209

1 p = 209 ÷ 11 = 19

Number of balloons that Lee used
= 1 p + 4 p
= 5 p
= 5 x 19
= 95

Number of balloons that Lee had in the end
= 171 - 95
= 76

Answer(s): 76