Bobby bought 176 blue and gold balloons for a party. The number of gold balloons was
47 times as many as the number of blue balloons. Bobby used
13 times as many gold balloons as blue balloons and was left with twice as many gold balloons as blue balloons. How many balloons did Bobby have in the end?
|
Gold (1) |
Blue (2) |
Make b the same. (2)x2 = (3) |
Before |
64 |
112 |
224 |
Change |
- 1 p |
- 3 p |
- 6 p |
After |
2 b |
1 b |
2 b |
Number of gold balloons that Bobby bought at first = 4 u
Number of blue balloons that Bobby bought at first = 7 u
Total number of balloons at first
= 4 u + 7 u
= 11 u
11 u = 176
1 u = 176 ÷ 11 = 16
Number of gold balloons at first
= 4 u
= 4 x 16
= 64
Number of blue balloons at first
= 7 u
= 7 x 16
= 112
64 - 1 p =
2 b --- (1)
112 - 3 p = 1 b --- (2)
(2)
x2
224 - 6 p =
2 b --- (3)
(3) = (1)
224 - 6 p = 64 - 1 p
6 p - 1 p = 224 - 64
5 p = 160
1 p = 160 ÷ 5 = 32
Number of balloons that Bobby used
= 1 p + 3 p
= 4 p
= 4 x 32
= 128
Number of balloons that Bobby had in the end
= 176 - 128
= 48
Answer(s): 48