Fred bought 88 silver and red balloons for a party. The number of red balloons was
35 times as many as the number of silver balloons. Fred used
13 times as many red balloons as silver balloons and was left with four times as many red balloons as silver balloons. How many balloons did Fred have in the end?
|
Red (1) |
Silver (2) |
Make b the same. (2)x4 = (3) |
Before |
33 |
55 |
220 |
Change |
- 1 p |
- 3 p |
- 12 p |
After |
4 b |
1 b |
4 b |
Number of red balloons that Fred bought at first = 3 u
Number of silver balloons that Fred bought at first = 5 u
Total number of balloons at first
= 3 u + 5 u
= 8 u
8 u = 88
1 u = 88 ÷ 8 = 11
Number of red balloons at first
= 3 u
= 3 x 11
= 33
Number of silver balloons at first
= 5 u
= 5 x 11
= 55
33 - 1 p =
4 b --- (1)
55 - 3 p = 1 b --- (2)
(2)
x4
220 - 12 p =
4 b --- (3)
(3) = (1)
220 - 12 p = 33 - 1 p
12 p - 1 p = 220 - 33
11 p = 187
1 p = 187 ÷ 11 = 17
Number of balloons that Fred used
= 1 p + 3 p
= 4 p
= 4 x 17
= 68
Number of balloons that Fred had in the end
= 88 - 68
= 20
Answer(s): 20