Eric bought 120 grey and blue balloons for a party. The number of blue balloons was
35 times as many as the number of grey balloons. Eric used
14 times as many blue balloons as grey balloons and was left with twice as many blue balloons as grey balloons. How many balloons did Eric have in the end?
|
Blue (1) |
Grey (2) |
Make b the same. (2)x2 = (3) |
Before |
45 |
75 |
150 |
Change |
- 1 p |
- 4 p |
- 8 p |
After |
2 b |
1 b |
2 b |
Number of blue balloons that Eric bought at first = 3 u
Number of grey balloons that Eric bought at first = 5 u
Total number of balloons at first
= 3 u + 5 u
= 8 u
8 u = 120
1 u = 120 ÷ 8 = 15
Number of blue balloons at first
= 3 u
= 3 x 15
= 45
Number of grey balloons at first
= 5 u
= 5 x 15
= 75
45 - 1 p =
2 b --- (1)
75 - 4 p = 1 b --- (2)
(2)
x2
150 - 8 p =
2 b --- (3)
(3) = (1)
150 - 8 p = 45 - 1 p
8 p - 1 p = 150 - 45
7 p = 105
1 p = 105 ÷ 7 = 15
Number of balloons that Eric used
= 1 p + 4 p
= 5 p
= 5 x 15
= 75
Number of balloons that Eric had in the end
= 120 - 75
= 45
Answer(s): 45