Sam bought 154 white and silver balloons for a party. The number of silver balloons was
47 times as many as the number of white balloons. Sam used
12 times as many silver balloons as white balloons and was left with four times as many silver balloons as white balloons. How many balloons did Sam have in the end?
|
Silver (1) |
White (2) |
Make b the same. (2)x4 = (3) |
Before |
56 |
98 |
392 |
Change |
- 1 p |
- 2 p |
- 8 p |
After |
4 b |
1 b |
4 b |
Number of silver balloons that Sam bought at first = 4 u
Number of white balloons that Sam bought at first = 7 u
Total number of balloons at first
= 4 u + 7 u
= 11 u
11 u = 154
1 u = 154 ÷ 11 = 14
Number of silver balloons at first
= 4 u
= 4 x 14
= 56
Number of white balloons at first
= 7 u
= 7 x 14
= 98
56 - 1 p =
4 b --- (1)
98 - 2 p = 1 b --- (2)
(2)
x4
392 - 8 p =
4 b --- (3)
(3) = (1)
392 - 8 p = 56 - 1 p
8 p - 1 p = 392 - 56
7 p = 336
1 p = 336 ÷ 7 = 48
Number of balloons that Sam used
= 1 p + 2 p
= 3 p
= 3 x 48
= 144
Number of balloons that Sam had in the end
= 154 - 144
= 10
Answer(s): 10