Archie bought 144 black and red balloons for a party. The number of red balloons was
35 times as many as the number of black balloons. Archie used
14 times as many red balloons as black balloons and was left with twice as many red balloons as black balloons. How many balloons did Archie have in the end?
|
Red (1) |
Black (2) |
Make b the same. (2)x2 = (3) |
Before |
54 |
90 |
180 |
Change |
- 1 p |
- 4 p |
- 8 p |
After |
2 b |
1 b |
2 b |
Number of red balloons that Archie bought at first = 3 u
Number of black balloons that Archie bought at first = 5 u
Total number of balloons at first
= 3 u + 5 u
= 8 u
8 u = 144
1 u = 144 ÷ 8 = 18
Number of red balloons at first
= 3 u
= 3 x 18
= 54
Number of black balloons at first
= 5 u
= 5 x 18
= 90
54 - 1 p =
2 b --- (1)
90 - 4 p = 1 b --- (2)
(2)
x2
180 - 8 p =
2 b --- (3)
(3) = (1)
180 - 8 p = 54 - 1 p
8 p - 1 p = 180 - 54
7 p = 126
1 p = 126 ÷ 7 = 18
Number of balloons that Archie used
= 1 p + 4 p
= 5 p
= 5 x 18
= 90
Number of balloons that Archie had in the end
= 144 - 90
= 54
Answer(s): 54