Cody, Howard and Lee had a total of 573 cards at first. After a week, the number of Cody's cards became 4 times the number of cards he had at first. The number of Howard's cards decreased by 27. Lee had one-quarter as many cards as he had at first. In the end, the three boys had the same number of cards.
- How many cards did Lee have at first?
- What was the total number of cards that the three boys had in the end?
|
Cody |
Howard |
Lee |
Total |
Before |
1 u |
4 u + 27 |
16 u |
|
Change |
x 4 |
- 27 |
x 14 |
|
After |
4 u |
4 u |
4 u |
12 u |
(a)
Total number of cards at first
=
1 u + 4 u + 27 + 16 u
= 21 u + 27
21 u + 27 = 57321 u = 573 - 2721 u = 546
1 u = 546 ÷ 21 = 26 Number of cards that Lee had at first
= 4 u ÷
14= 4 u x
41= 16 u = 16 x 26 = 416(b)Total number of cards that the three boys had at the end = 12 u = 12 x 26 = 312 Answer(s): (a) 416; (b) 312