Andy, Ivan and Xavier had a total of 541 erasers at first. After a week, the number of Andy's erasers became 4 times the number of erasers he had at first. The number of Ivan's erasers decreased by 268. Xavier had one-quarter as many erasers as he had at first. In the end, the three boys had the same number of erasers.
- How many erasers did Xavier have at first?
- What was the total number of erasers that the three boys had in the end?
|
Andy |
Ivan |
Xavier |
Total |
Before |
1 u |
4 u + 268 |
16 u |
|
Change |
x 4 |
- 268 |
x 14 |
|
After |
4 u |
4 u |
4 u |
12 u |
(a)
Total number of erasers at first
=
1 u + 4 u + 268 + 16 u
= 21 u + 268
21 u + 268 = 54121 u = 541 - 26821 u = 273
1 u = 273 ÷ 21 = 13 Number of erasers that Xavier had at first
= 4 u ÷
14= 4 u x
41= 16 u = 16 x 13 = 208(b)Total number of erasers that the three boys had at the end = 12 u = 12 x 13 = 156 Answer(s): (a) 208; (b) 156