Ken, Pierre and Ben had a total of 495 stamps at first. After a week, the number of Ken's stamps became 5 times the number of stamps he had at first. The number of Pierre's stamps decreased by 63. Ben had half as many stamps as he had at first. In the end, the three boys had the same number of stamps.
- How many stamps did Ben have at first?
- What was the total number of stamps that the three boys had in the end?
|
Ken |
Pierre |
Ben |
Total |
Before |
1 u |
5 u + 63 |
10 u |
|
Change |
x 5 |
- 63 |
x 12 |
|
After |
5 u |
5 u |
5 u |
15 u |
(a)
Total number of stamps at first
=
1 u + 5 u + 63 + 10 u
= 16 u + 63
16 u + 63 = 49516 u = 495 - 6316 u = 432
1 u = 432 ÷ 16 = 27 Number of stamps that Ben had at first
= 5 u ÷
12= 5 u x
21= 10 u = 10 x 27 = 270(b)Total number of stamps that the three boys had at the end = 15 u = 15 x 27 = 405 Answer(s): (a) 270; (b) 405