Luke, Fred and Zane had a total of 591 pens at first. After a week, the number of Luke's pens became 4 times the number of pens he had at first. The number of Fred's pens decreased by 234. Zane had one-quarter as many pens as he had at first. In the end, the three boys had the same number of pens.
- How many pens did Zane have at first?
- What was the total number of pens that the three boys had in the end?
|
Luke |
Fred |
Zane |
Total |
Before |
1 u |
4 u + 234 |
16 u |
|
Change |
x 4 |
- 234 |
x 14 |
|
After |
4 u |
4 u |
4 u |
12 u |
(a)
Total number of pens at first
=
1 u + 4 u + 234 + 16 u
= 21 u + 234
21 u + 234 = 59121 u = 591 - 23421 u = 357
1 u = 357 ÷ 21 = 17 Number of pens that Zane had at first
= 4 u ÷
14= 4 u x
41= 16 u = 16 x 17 = 272(b)Total number of pens that the three boys had at the end = 12 u = 12 x 17 = 204 Answer(s): (a) 272; (b) 204